Duplicate Elements: Find duplicates in an array
This program demonstrates how to find duplicate elements in an array using Java. The algorithm iterates through the array and uses a HashSet to track seen elements. If an element is found in the HashSet, it is identified as a duplicate.
Java Program
import java.util.HashSet;
public class DuplicateElements {
/**
* Finds and prints duplicate elements in the given array.
*
* @param array The array to check for duplicates.
*/
public static void findDuplicates(int[] array) {
HashSet<Integer> seen = new HashSet<>();
HashSet<Integer> duplicates = new HashSet<>();
for (int element : array) {
if (!seen.add(element)) {
duplicates.add(element);
}
}
if (duplicates.isEmpty()) {
System.out.println("No duplicates found.");
} else {
System.out.println("Duplicate elements: " + duplicates);
}
}
public static void main(String[] args) {
int[] array = {1, 2, 3, 4, 5, 6, 7, 2, 3, 8, 9, 10, 10};
findDuplicates(array);
}
}
Explanation
The program includes the following components:
import java.util.HashSet;: Imports theHashSetclass from the Java Collections Framework.public class DuplicateElements: Defines the main class.public static void findDuplicates(int[] array): Defines a static method that takes an array of integers as input and prints the duplicate elements.HashSet<Integer> seen = new HashSet<>();: Initializes aHashSetto keep track of elements that have been encountered in the array.HashSet<Integer> duplicates = new HashSet<>();: Initializes aHashSetto store duplicate elements.for (int element : array): Iterates through each element in the array.if (!seen.add(element)): Checks if the element can be added to theseenset. If it returnsfalse, it means the element is a duplicate.duplicates.add(element): Adds the duplicate element to theduplicatesset.if (duplicates.isEmpty()): Checks if theduplicatesset is empty and prints an appropriate message.public static void main(String[] args): The main method that initializes an array and calls thefindDuplicatesmethod.
The example array int[] array = {1, 2, 3, 4, 5, 6, 7, 2, 3, 8, 9, 10, 10}; contains the duplicates 2, 3, and 10. When the findDuplicates method is called, it will print:
No duplicates found. Duplicate elements: [2, 3, 10]
Explanation
- Java Program: The provided Java program utilizes the
HashSetclass to identify duplicate elements in an array. ThefindDuplicatesmethod iterates through the array, adding each element to aHashSetcalledseen. If an element cannot be added (because it is already in theseenset), it is added to aHashSetcalledduplicates. - Output: The output of the program will list all the duplicate elements found in the array.
