FizzBuzz Program in C

This program prints numbers from 1 to 100, replacing multiples of 3 with “Fizz”, multiples of 5 with “Buzz”, and multiples of both with “FizzBuzz”.

Program Structure

The structure of the program is as follows:

• Include necessary libraries: The program includes the standard input-output library using #include <stdio.h>.
• Main function: The program contains the main function where the logic is implemented.
• Loop through numbers 1 to 100: A for loop is used to iterate through numbers from 1 to 100.
• Condition checks: Within the loop, if statements are used to check if a number is a multiple of 3, 5, or both, and print the corresponding output.

FizzBuzz Program

#include <stdio.h>

/**
 * main - Entry point of the program
 *
 * Description:
 * This function iterates through numbers 1 to 100 and prints "Fizz" for multiples
 * of 3, "Buzz" for multiples of 5, and "FizzBuzz" for multiples of both 3 and 5.
 * For other numbers, it simply prints the number itself.
 *
 * Return: Always 0 (Success)
 */
int main() {
    for (int i = 1; i <= 100; i++) {
        // Check if the number is a multiple of both 3 and 5
        if (i % 3 == 0 && i % 5 == 0) {
            printf("FizzBuzz\n");
        }
        // Check if the number is a multiple of 3
        else if (i % 3 == 0) {
            printf("Fizz\n");
        }
        // Check if the number is a multiple of 5
        else if (i % 5 == 0) {
            printf("Buzz\n");
        }
        // If the number is not a multiple of 3 or 5, print the number
        else {
            printf("%d\n", i);
        }
    }
    return 0;
}

Explanation of the Program

The program starts by including the standard input-output library <stdio.h> which is necessary for using the printf function.

In the main function, a for loop is used to iterate through numbers from 1 to 100. For each number, the following checks are performed:

1. If the number is a multiple of both 3 and 5 (i.e., i % 3 == 0 && i % 5 == 0), the program prints “FizzBuzz”.
2. If the number is a multiple of 3 (i.e., i % 3 == 0), the program prints “Fizz”.
3. If the number is a multiple of 5 (i.e., i % 5 == 0), the program prints “Buzz”.
4. If the number is not a multiple of 3 or 5, the program prints the number itself.

This process continues until all numbers from 1 to 100 are processed and printed accordingly.